Class 7 The Triangle and its Properties Ex 6.2

 

NCERT Solutions For Class 7 Maths Chapter 6 – The Triangle and its Properties Ex 6.2

Simple solutions for NCERT Solutions for Class 7 Maths Exercise 6.2 Chapter 6 The Triangle and its Properties are given here in the post. This NCERT Solutions for Class 7 Maths Exercise 6.2 contains topics related to the raw data collection and its organisation. so we definitely want students of Class 7 to solve Class 7 The Triangle and its Properties NCERT Exercise 6.2 to empower their basics and test the students capability of understanding the concepts. It also helps the students of CBSE Class 7 Maths students.

1. Find the value of the unknown exterior angle x in the following diagram:

(i)

Solution:-

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

x = 50o + 70o

x = 120o

(ii)

Solution:-

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

 x = 65o + 45o

 x = 110o

(iii)

Solution:-

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

x = 30o + 40o

x = 70o

(iv)

Solution:-

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

x = 60o + 60o

x = 120o

(v)

Solution:-

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

x = 50o + 50o

x = 100o

(vi)

Solution:-

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

x = 30o + 60o

x = 90o

2. Find the value of the unknown interior angle x in the following figures:

(i)

Solution:-

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

x + 50o = 115o

x = 115o – 50o

x = 65o

(ii)

Solution:-

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

70o + x = 100o

x = 100o – 70o

x = 30o

(iii)

Solution:-

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

The given triangle is a right-angled triangle. So, the angle opposite to the x is 90o.

x + 90o = 125o

x = 125o – 90o

x = 35o

(iv)

Solution:-

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

 x + 60o = 120o

 x = 120o – 60o

 x = 60o

(v)

Solution:-

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

The given triangle is a right-angled triangle. So, the angle opposite to the x is 90o.

 x + 30o = 80o

 x = 80o – 30o

 x = 50o

(vi)

Solution:-

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

The given triangle is a right-angled triangle. So, the angle opposite to the x is 90o.

 x + 35o = 75o

 x = 75o – 35o

 x = 40o