Class 7 Rational Numbers Exercise 8.1


1. List five rational numbers between

(i) \(-1\) and \(0\)

Solution:

The five rational numbers between \(-1\) and \(0\) are

\(-1 , ({-2\over3}) , ({-3\over4}) , ({-4\over5}), ({-5\over6}) , ({-6\over7}) , 0\)

(ii) \(-2\) and \(-1\)

Solution:

The five rational numbers between \(-2\) and \(-1\) are

\(-2 , ({-8\over7}) , ({-9\over8}), ({-10\over9}) , ({-11\over10}) ,({-12\over11}) ,-1\)

(iii) \({-4\over5}\) and \({-2\over3}\)

Solution:

The five rational numbers between \({-4\over5}\) and \({-2\over3}\) are

\({-4\over5}, ({-13\over12}), ({-14\over13}) , ({-15\over14}), ({-16\over15}) , ({-17\over16}) , {-2\over3}\)

(iv) \({-1\over2}\) and \({2\over3}\)

Solution:

The five rational numbers between \({-1\over2}\) and \({2\over3}\) are

\({-1\over2}, {(-1\over6)}, (0), ({1\over3}) , ({1\over2}) , ({20\over36}) , {2\over3}\)

2. Write four more rational numbers in each of the following patterns.

(i)\(\frac{-3}{5},\ \frac{-6}{10},\ \frac{-9}{15},\ \frac{-12}{20}\)

Next four fractions:
\(\frac{-15}{25},\ \frac{-18}{30},\ \frac{-21}{35},\ \frac{-24}{40}\)

(ii)\(\frac{-1}{4},\ \frac{-2}{8},\ \frac{-3}{12}\)

Next four fractions:
\(\frac{-4}{16},\ \frac{-5}{20},\ \frac{-6}{24},\ \frac{-7}{28}\)

(iii)\(\frac{-1}{6},\ \frac{2}{-12},\ \frac{3}{-18},\ \frac{4}{-24}\)

Next four fractions:

\(\frac{5}{-30},\ \frac{6}{-36},\ \frac{7}{-42},\ \frac{8}{-48}\)

(iv)\(\frac{-2}{3},\ \frac{2}{-3},\ \frac{4}{-6},\ \frac{6}{-9}\)

Next four fractions:
\(\frac{8}{-12},\ \frac{10}{-15},\ \frac{12}{-18},\ \frac{14}{-21}\)

3. Give four rational numbers equivalent to:
(i) \( -\frac{2}{7} \)

\(\frac{-2n}{7n}=\frac{-2 \times 2}{7 \times 2},\ \frac{-2 \times 3}{7 \times 3},\ \frac{-2 \times 4}{7 \times 4},\ \frac{-2 \times 5}{7 \times 5} \)

Equivalent fractions:  \( \frac{4}{14},\ -\frac{6}{21},\ -\frac{8}{28},\ -\frac{10}{35}\)

(ii) \( \frac{5}{-3} \) 

\(\frac{5n}{-3n} = \frac{5 \times 2}{-3 \times 2},\ \frac{5 \times 3}{-3 \times 3},\ \frac{5 \times 4}{-3 \times 4},\ \frac{5 \times 5}{-3 \times 5} \)

Equivalent fractions: 

\(\frac{10}{-6},\ \frac{15}{-9},\ \frac{20}{-12},\ \frac{25}{-15}\)

(iii) \( \frac{4}{9} \)

\(\frac{4n}{9n}=\frac{4 \times 2}{9 \times 2},\frac{4 \times 3}{9 \times 3},\frac{4 \times 4}{9 \times 4},\frac{4 \times 5}{9 \times 5}\)

Equivalent fractions: \(\frac{8}{18},\ \frac{12}{27},\ \frac{16}{36}, \frac{20}{45}\)

4. Draw the number line and represent the following rational numbers on it.

(i) \(\dfrac{3}{4}\)

Solution:


We know that \(\dfrac{3}{4}\) is greater than 0 and less than 1.

∴ it lies between 0 and 1. It can be represented on the number line as



(ii) \(\dfrac{-5}{8}\) 

Solution:

We know that \(\dfrac{-5}{8}\) is less than 0 and greater than -1.

∴ it lies between 0 and -1. It can be represented on the number line as



(iii) \(\dfrac{-7}{4}\)

Solution:


\(\dfrac{-7}{4}= -1\dfrac{3}{4}\)

We know that \(\dfrac{-7}{4}\) is less than -1 and greater than -2.

∴ it lies between -1 and -2. It can be represented on the number line as


(iv) \(\dfrac{7}{8}\)

Solution:


We know that \(\dfrac{7}{8}\) is greater than 0 and less than 1.

∴ it lies between 0 and 1. It can be represented on the number line as


5. The points P, Q, R, S, T, U, A and B on the number line are such that TR = RS = SU and AP = PQ = QB. Name the rational numbers represented by P, Q, R and S.



Solution:


By observing the figure, we can say that

The distance between A and B = 1 unit

And it is divided into 3 equal parts = AP = PQ = QB = \(\dfrac{2}{3}\)

P = \(2 + \dfrac{2}{3}= \dfrac{(6 + 1)}{3} = \dfrac{7}{3}\)

Q =\( 2 + \dfrac{2}{3} = \dfrac{(6 + 2)}{3} = \dfrac{8}{3}\)

The distance between U and T = 1 unit

And it is divided into 3 equal parts = TR = RS = SU = \(\dfrac{1}{3}\)

R \(= – 1 – \dfrac{1}{3}\)

\(= \dfrac{-3-1}{3}\)

\(= \dfrac{-4}{3}\)

S\( = – 1 – (\dfrac{2}{3})\)

\(= \dfrac{-3-2}{3}\)

\(= \dfrac{-5}{3}\)

6. Which of the following pairs represent the same rational number
(i) \( \frac{-7}{21} \) and \( \frac{3}{9} \)

\(\frac{-7}{21} = -\frac{1}{3}, \qquad \frac{3}{9} = \frac{1}{3}\)

\(-\frac{1}{3} \ne \frac{1}{3}\)

∴ \( \frac{-7}{21} \ne \frac{3}{9} \)

They do not represent the same rational number.


(ii) \( \frac{-16}{20} \) and \( \frac{20}{-25} \)

\(\frac{-16}{20} = -\frac{4}{5}, \qquad \frac{20}{-25} = -\frac{4}{5}\)

\(-\frac{4}{5} = -\frac{4}{5}\)

∴ \( \frac{-16}{20} = \frac{20}{-25} \)

They represent the same rational number.


(iii) \( \frac{-2}{-3} \) and \( \frac{2}{3} \)

\(\frac{-2}{-3} = \frac{2}{3}\)

\(\frac{2}{3} = \frac{2}{3}\)

∴ \( \frac{-2}{-3} = \frac{2}{3} \)

They represent the same rational number.


(iv) \( \frac{-3}{5} \) and \( \frac{-12}{20} \)

\(\frac{-12}{20} = -\frac{3}{5} \)

\(-\frac{3}{5} = -\frac{3}{5} \)

∴ \( \frac{-3}{5} = \frac{-12}{20} \)

They represent the same rational number.



(v) \( \frac{8}{-5} \) and \( \frac{-24}{15} \)

\(\frac{8}{-5} = -\frac{8}{5}, \qquad \frac{-24}{15} = -\frac{8}{5}\)

\(-\frac{8}{5} = -\frac{8}{5}\)

∴ \( \frac{8}{-5} = \frac{-24}{15}\)

They represent the same rational number.



(vi) \( \frac{1}{3} \) and \( \frac{-1}{9} \)

\(\frac{1}{3} \ne -\frac{1}{9}\)

∴ \( \frac{1}{3} \ne \frac{-1}{9} \)

They do not represent the same rational number.


(vii) \( \frac{-5}{-9} \) and \( \frac{5}{-9} \)

\(\frac{-5}{-9} = \frac{5}{9}, \qquad \frac{5}{-9} = -\frac{5}{9}\)

\(\frac{5}{9} \ne -\frac{5}{9}\)

\(∴ ( \frac{-5}{-9} \ne \frac{5}{-9} )\)

They do not represent the same rational number.

7. Rewrite the following rational numbers in the simplest form

(i) \( \frac{-8}{6} =\frac{-4}{3}\)

✅ Simplest form: \(-\frac{4}{3}\)


(ii) \( \frac{25}{45} =\frac{5}{9}\)

✅ Simplest form: \(\frac{5}{9}\)


(iii) \( \frac{-44}{72} =\frac{-11}{18}\)

✅ Simplest form: \(-\frac{11}{18}\)


(iv) \( \frac{-8}{10}=\frac{-4}{5} \)

✅ Simplest form: \(-\frac{4}{5}\)

8. Fill in the boxes with the correct symbol (>), (<), or (=)

(i) \( -\frac{5}{7}\Box \frac{2}{3} \)

LCM of 7 and 3 = 21

\(-\frac{5}{7} = -\frac{15}{21}, \qquad \frac{2}{3} = \frac{14}{21}\)

Since (-15 < 14)

∴ \(-\frac{5}{7} < \frac{2}{3}\)

(ii) \( -\frac{4}{5} \Box -\frac{5}{7} \)

LCM of 5 and 7 = 35

\(-\frac{4}{5} = -\frac{28}{35}, \qquad -\frac{5}{7} = -\frac{25}{35}\)

Since \(-28 < -25\)

∴ \(-\frac{4}{5} < -\frac{5}{7}\)

(iii) \( -\frac{7}{8} \Box \frac{14}{-16} \)

Simplify:

\(\frac{14}{-16} = -\frac{7}{8}\)

∴ \(-\frac{7}{8} = \frac{14}{-16}\)

(iv) \( -\frac{8}{5}\Box -\frac{7}{4} \)

LCM of 5 and 4 = 20

\(-\frac{8}{5} = -\frac{32}{20}, \qquad -\frac{7}{4} = -\frac{35}{20}\)

Since \(-32 > -35\)

∴ \(-\frac{8}{5} > -\frac{7}{4}\)

(v) \( \frac{1}{-3} \Box -\frac{1}{4} \)

\(\frac{1}{-3} = -\frac{1}{3}\)

LCM of 3 and 4 = 12

\(-\frac{1}{3} = -\frac{4}{12}, \qquad -\frac{1}{4} = -\frac{3}{12}\)

 \(-4 < -3\)

∴ \(\frac{1}{-3} < -\frac{1}{4}\)

(vi) \( \frac{5}{-11} \Box -\frac{5}{11} \)

\(\frac{5}{-11} = -\frac{5}{11}\)

∴ \(\frac{5}{-11} = -\frac{5}{11}\)

(vii) \( 0  \Box -\frac{7}{6} \)

Every negative number is less than 0.

∴ \(0 > -\frac{7}{6}\)

✅ Final answers (quick view):

\( -\frac{5}{7} < \frac{2}{3} \)


\( -\frac{4}{5} < -\frac{5}{7} \)


\( -\frac{7}{8} = \frac{14}{-16} \)


\( -\frac{8}{5} > -\frac{7}{4} \)


\( \frac{1}{-3} < -\frac{1}{4} \)


\( \frac{5}{-11} = -\frac{5}{11} \)


\( 0 > -\frac{7}{6} \)

9. Which is greater in each of the following?

(i) \( \frac{2}{3} , \frac{5}{2} \)

LCM of 3 and 2 = 6

\(\frac{2}{3} = \frac{4}{6}, \qquad \frac{5}{2} = \frac{15}{6}\)

Since \((4 < 15)\)

\(\frac{2}{3} < \frac{5}{2}\)

✅ \( \frac{5}{2} \) is greater.


(ii) \( -\frac{5}{6} , -\frac{4}{3} \)

LCM of 6 and 3 = 6

\( -\frac{5}{6} = -\frac{5}{6}, \qquad -\frac{4}{3} = -\frac{12}{6}\)

Since (-5 > -12)

\(-\frac{5}{6} > -\frac{4}{3}\)

✅ \( -\frac{5}{6} \) is greater.


(iii) \( -\frac{3}{4} , \frac{2}{-3} \)

\(\frac{2}{-3} = -\frac{2}{3}\)

LCM of 4 and 3 = 12

\(-\frac{3}{4} = -\frac{9}{12}, \qquad -\frac{2}{3} = -\frac{8}{12}\)

Since (-9 < -8)

\(-\frac{3}{4} < -\frac{2}{3}\)

✅ \( \frac{2}{-3} \) (or \(-\frac{2}{3}\) is greater.


(iv) \( -\frac{1}{4} , \frac{1}{4} \)

A negative number is always less than a positive number.

\(-\frac{1}{4} < \frac{1}{4}\)

✅ \( \frac{1}{4} \) is greater.


(v) \(-3\frac{2}{7} > -3\frac{4}{5}\)

LCM of 7 and 5 = 35

\(-\frac{23}{7} = -\frac{115}{35}\)

\(-\frac{19}{5} = -\frac{133}{35}\)

Since \((-115 > -133)\)

\(-3\frac{2}{7} > -3\frac{4}{5}\)

\( -3\frac{2}{7} \) is greater.

10. Write the following rational numbers in ascending order

(i) \( -\frac{3}{5},\ -\frac{2}{5},\ -\frac{1}{5} \)

All fractions have the same denominator (5), so compare the numerators.

\(-3 < -2 < -1\)

\(\therefore -\frac{3}{5} < -\frac{2}{5} < -\frac{1}{5}\)

Ascending order:

\(-\frac{3}{5},\ -\frac{2}{5},\ -\frac{1}{5}\)


(ii) \( -\frac{1}{3},\ -\frac{2}{9},\ -\frac{4}{3} \)

LCM of 3, 9, 3 = 9

\(-\frac{1}{3} = -\frac{3}{9}, \qquad -\frac{2}{9} = -\frac{2}{9}, \qquad -\frac{4}{3} = -\frac{12}{9}\)

Compare:

\(-12 < -3 < -2\)

\(-\frac{4}{3} < -\frac{1}{3} < -\frac{2}{9}\)

Ascending order:

\(-\frac{4}{3},\ -\frac{1}{3},\ -\frac{2}{9}\)


(iii) \( -\frac{3}{7},\ -\frac{3}{2},\ -\frac{3}{4} \)

LCM of 7, 2, 4 = 28

\(-\frac{3}{7} = -\frac{12}{28}, \qquad -\frac{3}{2} = -\frac{42}{28}, \qquad -\frac{3}{4} = -\frac{21}{28}\)

\(-42 < -21 < -12\)

\(-\frac{3}{2} < -\frac{3}{4} < -\frac{3}{7}\)

Ascending order:

\(-\frac{3}{2},\ -\frac{3}{4},\ -\frac{3}{7}\)



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