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Class 6 Ratio and Proportion Ex 12.3

1. If the cost of 7 m of cloth is  1470, find the cost of 5 m of cloth. 
Solutions: 
Cost of 7 m cloth = ₹ 1470 
Cost of 1 m cloth = \(1470 \over 7\)  = ₹ 210 
 So, cost of 5 m cloth = 210 × 5 = 1050 
 ∴ Cost of 5 m cloth is ₹ 1050 

2. Ekta earns ₹3000 in 10 days. How much will she earn in 30 days? 
Solutions: 
 Money earned by Ekta in 10 days = ₹ 3000 
 Money earned in one day by her = \(3000 \over 10\)  = ₹ 300 
 So, money earned by her in 30 days = 300 × 30 = ₹ 9000 

3. If it has rained 276 mm in the last 3 days, how many cm of rain will fall in one full week (7 days)? Assume that the rain continues to fall at the same rate. 
Solutions: 
 Measure of rain in 3 days = 276 mm 
 Measure of rain in one day = 276 / 3 = 92 mm 
 So, measure of rain in one week, i.e. 7 days = 92 × 7 = 644 mm = \(644 \over 10\)  = 64.4 cm 

4. Cost of 5 kg of wheat is ₹ 91.50. 
(a) What will be the cost of 8 kg of wheat?
(b) What quantity of wheat can be purchased in ₹ 183?
Solutions:
(a) Cost of 5 kg wheat = ₹ 91.50. 
 Cost of 1 kg wheat = \(91.50 \over 5\)  = ₹ 18.3 
 So, the cost of 8 kg wheat = 18.3 × 8 = ₹ 146.40 
 (b) Wheat purchased in ₹ 91.50 = 5 kg 
 Wheat purchased in ₹ 1 = \(5\over 91.50 \) kg 
 So, wheat purchased in ₹ 183 = \(({5 \over 91.50})\) × 183 = 10 kg 

5. The temperature dropped 15 degree celsius in the last 30 days. If the rate of temperature drop remains the same, how many degrees will the temperature drop in the next ten days? 
Solutions:
Temperature drop in 30 days = \(150^{\circ}C\) 
Temperature drop in 1 day = \({15 \over 30}  = (1 / 2)^{\circ} C\) 
So, temperature drop in next 10 days = \({({1 \over 2})} × 10 = 50^{\circ} C\) 
 ∴ The temperature drop in the next 10 days will be \(50^{\circ}C\) 

6. Shaina pays  15000 as rent for 3 months. How much does she has to pay for a whole year, if the rent per month remains same? 
Solutions: 
 Rent paid by Shaina in 3 months = ₹ 15000 
 Rent for 1 month = \(15000 \over 3\)  = ₹ 5000 
 So, rent for 12 months, i.e. 1 year = 5000 × 12 = ₹ 60,000 
 ∴ Rent paid by Shaina in 1 year is ₹ 60,000 

7. Cost of 4 dozen bananas is  180. How many bananas can be purchased for  90? 
Solutions: 
 Number of bananas bought in ₹ 180 = 4 dozens = 4 × 12 = 48 bananas 
 Number of bananas bought in ₹ 1 = \(48 \over 180 \)
 So, number of bananas bought in ₹ \(90 = ({48 \over 180}) × 90 = 24\) bananas 
 ∴ 24 bananas can be purchased for ₹ 90 

8. The weight of 72 books is 9 kg. What is the weight of 40 such books? 

Solutions: 
 Weight of 72 books = 9 kg 
 Weight of 1 book = \({9 \over 72}  = {1 \over 8}\) kg 
 So, weight of 40 books = \(({1 \over 8}) × 40 = 5\) kg 
 ∴ Weight of 40 books is 5 kg 

9. A truck requires 108 litres of diesel for covering a distance of 594 km. How much diesel will be required by the truck to cover a distance of 1650 km? 

Solutions: 
 Diesel required for 594 km = 108 litres 
 Diesel required for 1 km = \({108 \over 594}  = {2 \over 11}\) litre 
 So, diesel required for 1650 km = (\({2 \over 11}\)) × 1650 = 300 litres 
 ∴ Diesel required by the truck to cover a distance of 1650 km is 300 litres 

10. Raju purchases 10 pens for  150 and Manish buys 7 pens for  84. Can you say who got the pens cheaper? 
Solutions: 
 Pens purchased by Raju for ₹ 150 = 10 pens 
 Cost of 1 pen = \(= {150 \over 10}\)  = ₹ 15 
 Pens purchased by Manish for ₹ 84 = 7 pens 
 Cost of 1 pen \(= {84 \over 7}  \)  = ₹ 12 
 ∴ Pens purchased by Manish are cheaper than Raju 

11. Anish made 42 runs in 6 overs and Anup made 63 runs in 7 overs. Who made more runs per over? 
Solutions: 
 Runs made by Anish in 6 overs = 42 
 Runs made by Anish in 1 over \(= {42 \over 6}  = 7\) 
 Runs made by Anup in 7 overs = 63 
 Runs made by Anup in 1 over \(= {63 \over 7}  = 9\) 
 ∴ Anup scored more runs than Anish.

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