class 6 mensuration Ex 10.2

1. Find the areas of the following figures by counting squares:

(a) The figure contains only 9 fully filled squares. Hence, the area of this figure will be 9 square units. 

 (b) The figure contains only 5 fully filled squares. Hence, the area of this figure will be 5 square units. 

 (c) The figure contains 2 fully filled squares and 4 half filled squares. Hence, the area of this figure will be 4 square units. 

 (d) The figure contains only 8 fully filled squares. Hence, the area of this figure will be 8 square units. 

 (e) The figure contains only 10 fully filled squares. Hence, the area of this figure will be 10 square units. 

 (f) The figure contains only 2 fully filled squares and 4 half filled squares. Hence, the area of this figure will be 4 square units. 

 (g) The figure contains 4 fully filled squares and 4 half filled squares. Hence, the area of this figure will be 6 square units. 

 (h) The figure contains 5 fully filled squares. Hence, the area of this figure will be 5 square units. 

 (i) The figure contains 9 fully filled squares. Hence, the area of this figure will be 9 square units. 

 (j) The figure contains 2 fully filled squares and 4 half filled squares. Hence, the area of this figure will be 4 square units. 

 (k) The figure contains 4 fully filled squares and 2 half filled squares. Hence, the area of this figure will be 5 square units. 

(l) From the given figure, we observe 

 \[\displaylines {\text{Covered Area}    &    \text{Number}&\text{ Area Estimate (square units)}\\ \text{Fully filled squares}  & {  2} &{  2 }\\ \text{Half filled squares}      &   {  2} &{  2 }  \\ \text{More than half filled squares}& 6& 6 \\ \text{Less than half filled squares} &6 &0 }\]

Therefore total area = 2 + 6 = 8 square units. 

(m) From the given figure, we observe

 \[\displaylines {\text{Covered Area}    &    \text{Number}&\text{ Area Estimate (square units)}\\ \text{Fully filled squares}  & {  5} &{  5 }\\ \text{Half filled squares}      &   {  9} &{  9 }  \\ \text{More than half filled squares}& 9& 9 \\ \text{Less than half filled squares} &12 &0 }\]

 Therefore total area = 5 + 9 = 14 square units 

 (n) From the given figure, we observe

 \[\displaylines {\text{Covered Area}    &    \text{Number}&\text{ Area Estimate (square units)}\\ \text{Fully filled squares}  & {  8} &{  8 }\\ \text{Half filled squares}      &   {  --} &{  -- }  \\ \text{More than half filled squares}& 10& 10 \\ \text{Less than half filled squares} &9 &0 }\]

 

 Therefore total area = 8 + 10 = 18 square units