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Class 6 Decimals Ex 8.4

Class 6 Decimals Ex 8.3
1. Subtract: 
 (a) ₹ 18.25 from ₹ 20.75 
 (b) 202.54 m from 250 m 
 (c) ₹ 5.36 from ₹ 8.40 
 (d) 2.051 km from 5.206 km 
 (e) 0.314 kg from 2.107 kg 

 Solutions: 
 (a) ₹ 20.75 – ₹ 18.75 =₹ 2.50
   \[ \displaylines{ 20.75\\ – 18.25 \\ \text{___________}\\2.50 \\ \text{___________}}\]
 (b) 250 m – 202.54 m =  47.46 m 
\[ \displaylines{ 250.00\\ – 202.54 \\ \text{___________}\\47.46 \\ \text{___________}}\]
 (c) ₹ 8.40 – ₹ 5.36 = ₹ 3.04 
\[ \displaylines{ 8.40\\ –5.36 \\ \text{___________}\\3.04 \\ \text{___________}}\]
 (d) 5.206 km – 2.051 km = 3.155 km 
\[ \displaylines{ 5.206\\ –2.051 \\ \text{___________}\\3.155 \\ \text{___________}}\]
 (e) 2.107 kg – 0.314 kg = 1.793 kg 
\[ \displaylines{ 2.107\\ –0.314 \\ \text{___________}\\1.793 \\ \text{___________}}\]

 2. Find the value of the following: 
 (a) 9.756 – 6.28 
 (b) 21.05 – 15.27 
 (c) 18.5 – 6.79 
 (d) 11.6 – 9.847 

 Solutions: 

 (a) 9.756 – 6.280 = 3.476 
\[ \displaylines{ 9.756\\ – 6.280 \\ \text{___________}\\3.476 \\ \text{___________}}\]

 (b) 21.05 – 15.27= 5.78 
\[ \displaylines{ 21.05\\ – 15.27 \\ \text{___________}\\5.78 \\ \text{___________}}\]

 (c) 18.50 – 6.79 = 11.71  
\[ \displaylines{ 18.50\\ – 6.79 \\ \text{___________}\\11.71 \\ \text{___________}}\]

 (d) 11.600 – 9.847= 1.753
\[ \displaylines{ 11.600\\ – 9.847 \\ \text{___________}\\1.753 \\ \text{___________}}\]

 3. Raju bought a book for ₹ 35.65. He gave ₹ 50 to the shopkeeper. How much money did he get back from the shopkeeper? 

 Solutions: 

 Money given to shopkeeper = ₹ 50.00 
 Price of the book = ₹ 35.65 

 ∴ The money left with Raju is 
\[ \displaylines{ 50.00\\ – 35.65 \\ \text{___________}\\14.35 \\ \text{___________}}\]
Hence, the money left with Raju is ₹ 14.35. 

 4. Rani had ₹ 18.50. She bought one ice cream for ₹ 11.75. How much money does she have now? 

 Solutions: 

 Money with Rani = ₹ 18.50 
 Price of an ice cream = ₹ 11.75 
 Hence, the money left with her is \[ \displaylines{ 18.50\\ – 11.75 \\ \text{___________}\\6.75 \\ \text{___________}}\]
  ∴ The money left with Rani is ₹ 6.75. 116 

5. Tina had 20 m 5 cm long cloth. She cuts 4 m 50 cm length of cloth from this for making a curtain. How much cloth is left with her? 

 Solutions: 

 Length of cloth = 20 m 5 cm = 20.05 m 
 Length of cloth to make a curtain = 4 m 50 cm = 4.50 m
 Thus, the length of cloth left with her is 20.05 – 4.50= 15.55
\[ \displaylines{ 20.05\\ – 4.50 \\ \text{___________}\\6.75 \\ \text{___________}}\]
 ∴ The length of the remaining cloth left with Tina is 15.55 m. 

 6. Namita travels 20 km 50 m every day. Out of this, she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto? 

 Solutions: 

 Total distance travelled by Namita = 20 km 50 m = 20.050 km 
 Distance travelled by bus = 10 km 200 m = 10.200 km 
 Distance travelled by auto = Total distance travelled – Distance travelled by bus 
 ∴ Distance to be travelled by auto is 20.050 – 10.200 ________ 9.850
\[ \displaylines{ 20.050\\ – 10.200 \\ \text{___________}\\9.850 \\ \text{___________}}\]
 ∴ Namita travelled 9.850 km by auto. 

 7. Aakash bought vegetables weighing 10 kg. Out of this, 3 kg 500 g is onions, 2 kg 75 g is tomatoes, and the rest is potatoes. What is the weight of the potatoes? 

 Solutions: 

 Total weight of vegetables Aakash bought = 10.000 kg 
 Weight of onions = 3 kg 500 g = 3.500 kg 
 Weight of tomatoes = 2 kg 75 g = 2.075 kg 
 Weight of potatoes = Total weight of vegetables bought – (weight of onions + weight of tomatoes) 
 = 10.000 – (3.500 + 2.075) = 4.425
 ∴ 4.425 kg is the weight of the potatoes.

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